In Rutherford experiment α -particle which approaches nucleus. Initial kinetic energy of α particle becomes equal to potential energy created by repulsion between α -particle and positively charged nucleus. By this fact minimum distance (deflection by 180º) between nucleus and α -particle.
r min = 
(i) For Rutherford experiment α -particle velocity
1.6 × 10 7 m/sec. Calculate minimum distance between collision, if scattering nucleus is copper
(Z = 29) –
Text Solution
Verified by Experts(i)[A]; (ii) [B]; (iii) [C]
(i)[A]
Sol. 1.6 × 10 –14 m
(ii) [B]
Sol. 2.88 × 10 –15 m
(iii) [C]
Sol. Most of the part of atom is empty and positive charge & mass is concentrated in nucleus
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